Math, asked by jdgupta, 10 months ago

If sec θ + tan θ =4/3 , then sec θ.tanθ is equals to?

Answers

Answered by yashqueryelite
1

Answer:

Step-by-step explanation:

sec+ tan = 4/3

As sec^2 - tan^2 = 1

( sec+ tan) ( sec - tan) = 1

sec - tan = 3/4

Add both

2 sec = 4/3 + 3/4 = 16 + 9)/ 12 = 25/12

sec = 25/24

subtract both

2tan = 4/3 - 3/4 = 16 - 9)/ 12 = 7/12

tan = 7/24

Sec tan = 25/24 × 7/24 = 175/576

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