If sec+tan=m and sec-tan=n find the value of √mn
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Hey!
[ Refer attachment ]
tan∅ = sin∅/cos∅
sec∅ = 1/cos∅
Sin²∅ + cos²∅ = 1
cos²∅ = 1 - sin²∅
• ( a + b ) ( a - b ) = a ² - b² !!
[ Refer attachment ]
tan∅ = sin∅/cos∅
sec∅ = 1/cos∅
Sin²∅ + cos²∅ = 1
cos²∅ = 1 - sin²∅
• ( a + b ) ( a - b ) = a ² - b² !!
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Answered by
2
Answer: + or - 1
Step-by-step explanation:
GIVEN: secA + tanA = m and secA - tanA = n
TO FIND: √mn = ?
SOLUTION:
√mn = √(secA + tanA)(secA-tanA) [by substituting what's given]
√mn = √sec²A - tan²A
√mn = √1 = + or - 1 [as sec²A - tan²A = 1]
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