If (secθ + tanθ) = m and (secθ - tanθ) = n, show that mn = 1
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(a+b)×(a-b) = a^2 -b^2
a = sec ø
b = tan ø
(Sec ø + tan ø)(sec ø -tan ø ) = sec^2 - tan^2 = 1
mn = 1
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