Question

If secθ + Tanθ = m and . secθ-Tanθ=n, then mn=_______​

Answer 1

Answer:

1

Step-by-step explanation:

mn=(secθ + Tanθ) × (secθ-Tanθ)

sec²θ-Tan²θ

1

Answer 2

Answer:

m= sec∅+tan∅

n= sec∅-tan∅

mn

=(sec∅+tan∅) (sec∅-tan∅)

=sec²∅ - tan²∅ {because (a+b)(a-b)=a²-b²}