Question

. If secθ + tanθ = p, prove that sinθ = 2−1 2+1

Answer 1

I can't understand what you written write properly. please for the answer.

Answer 2

Step-by-step explanation:

we know,sec^2theeta tan^2theeta=1

(sec the eta+tan theeta)(sec theeta -tan theeta)=1

sec theeta -tan theeta=1/p

sec theeta + tan theeta=p

adding,2 sec theeta=p+1/p=p^2+1/p

sec theeta=(p^2+1)/2p

cos theeta =2p/(p^2+1)

sin theeta =√(1-cos^2theeta)

=√{1-4p^2/(p^2+1)^2}

=√(p^4+2p^2+1-4p^2)/(p^2+1)^2

=√(p4-2p^2+1)/(p^2+1)^2

=√(p^2-1)^2/(p^2+1)^2

=p^2-1/p^2+1