Question

If, secθ + tanθ = p, then find the value of cosecθ

Answer 1

Answer:

( p²+1)/(p²-1)

Step-by-step explanation:

here I will write θ as A.

We know that,

1+ tan²A= sec²A

sec²A-tan²A = 1

(secA-tanA) (secA+ tanA) = 1

secA+ tanA = p

secA- tanA= 1/p

adding both equation,

2secA= (p²+1)/p

secA = (p²+1)/2p

Hypotenuse/Adjacent = (p²+1)/2p

subtracting both equation,

2tanA = (p²-1)/p

tanA= (p²-1)/2p

Opposite/Adjacent= (p²-1)/2p

CosecA= Hypotenuse/ Opposite

=( p²+1)/(p²-1)