If secθ+tanθ=p, then find the value of secθ-tanθ
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Here we have secθ+tanθ=p
now we know that sec²θ-tan²θ=1
so, sec²θ-tan²θ=1
(secθ-tanθ)(secθ+tanθ)=1
(secθ-tanθ)(p)=1
secθ-tanθ=1/p
now we know that sec²θ-tan²θ=1
so, sec²θ-tan²θ=1
(secθ-tanθ)(secθ+tanθ)=1
(secθ-tanθ)(p)=1
secθ-tanθ=1/p
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