Question

if secθ+tanθ=p,then find the value of sinθ interns of p.​

Answer 1

Answer:

let theta =@

sec@ + tan@=p------------------(1)

we know ,

sec^2@-tan^2@=1

(sec@-tan@)(sec@+tan@)=1

hence ,

sec@-tan@=1/p -----------------(2)

now equation (1)and (2)

2sec@=p+1/p=(p^2+1)/p

sec@=(p^2+1)/2p

hence,

cos@=2p/(1+p^2)

hence ,

sin@=(1-p^2)/(1+p^2)