Question

If sec + tan =p then s t sin p2-p1 /p2+p1

Answer 1

Answer :

Sin θ

Explanation :

p2-1

p2+1

= (sin θ + tan θ)sq - 1 / (sin θ + tan θ)sq +1

= sec sq. θ + tan sq.θ + 2 sec θ tan θ - 1 /

sec sq. θ + tan sq. θ + 2 sec θ tan θ + 1

= (sec sq. θ - 1) + tan sq. θ + 2 sec θ tan θ/

sec sq. θ + (tan sq. θ - 1) + 2 sec θ tan θ

= tan sq. θ + tan sq. θ + 2 sec θ tan θ /

sec sq. θ + sec sq. θ + 2 sec θ tan θ

= 2 tan sq. θ + 2 sec θ tan θ /

2 sec sq. θ + 2 sec θ tan θ

= 2 tan θ ( tan θ + sec θ) /

2 sec θ (sec θ + tan θ)

= 2 tan θ / 2 sec θ

= tan θ x cos θ

= sin θ / x cos θ

cos θ

= sin θ

HOPE THIS WILL HELP YOU !!