Question

If secθ+tanθ=p then what is value of secθ-tanθ​

Answer 1

Answer:

• Given secA + tan A = p

Recall the identity, sec2A – tan2A = 1

⇒ (secA + tan A)(secA – tanA) = 1

⇒ p × (secA – tanA) = 1

∴ (secA – tanA) = 1/p

Thanks,........

Answer 2

secθ+tanθ=p

We know that

$sec {}^{2} θ - tan {}^{2} θ=1$

$sec {}^{2} θ - tan {}^{2} θ=1 \\ (secθ+tanθ)(secθ - tanθ) = 1 \\ p(secθ - tanθ) = 1 \\ (secθ - tanθ) = \frac{1}{p}$

Using identity in second statement above

${a}^{2} - {b}^{2} = (a - b)(a + b)$