Question

If sec θ- tan θ=⅓, then (sec θ+tan θ)=​

Answer 1

Answer:

1

If sec A+ tan A= 1/3, then what is the value of sec A – tan A?

Aditya Raman

Answered January 29, 2018

secA + tanA = 1/3

multiplying both sides by (secA + tanA)

(secA+tanA)(secA−tanA) =(1/3) (secA−tanA)

(secA)^2−(tanA)^2 = (1/3) (secA−tanA)

1 = (1/3) (secA−tanA) since, (secA)^2−(tanA)^2 = 1

so (secA−tanA) = 3

Answer 2

Answer:

3

Step-by-step explanation:

Multiply (secΦ+tanΦ) in up and down.

(secΦ-tanΦ)(secΦ+tanΦ)/(secΦ+tanΦ)=1/3

=>(sec²Φ-tan²Φ)/(secΦ+tanΦ)=1/3

=>1/(secΦ+tanΦ)=1/3

=>(secΦ+tanΦ)=3 (solved)