If sec θ+ tan θ = x, then sec θ
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Answer:your answer as follows
Step-by-step explanation: we know that 1+tan^2 theta=sec^2theta then
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Answer:
Step-by-step explanation: let me assume theta as¢
Since
Sec^2¢-Tan^2=1
(Sec¢-Tan¢)(Sec¢+Tan¢)=1
Sec¢-Tan¢=1/x ------(1)
(since Sec¢+Tan¢=x) ----(2)
(1)+(2)
Sec¢+Tan¢+Sec¢-Tan¢=1/x+x
2Sec¢=x^2+1/x
Sec¢=x^2+1/2x
Is this correct
Yes it is. Sorry actually I took LCM of 1/x+x which should be (x^2+1)/x and I just missed x in denominator btw now I have edited my answer. This was a little mistake which I made.. sorry once again.
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