Question

if sec theata = 2 then find cot theata

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Answer 1

Answer:

Step-by-step explanation:

Let us assume theta as a

Seca=2

1+cota=seca

Cota=2-1=1

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Answer 2

Given, Here let theta be A for our convinience.

So we get=>

Sec A = 2

=>1/Cos A =2

=>Hypotenuse/base = 2/1

Let Hypotenuse be 2x and base be x.

Now,by using Pythagoras theorem=>

(Hypotenuse)^2 = (base)^2 + (perpendicular)2

=>(2x)^2 = x^2 + (P)^2

=>(P)^2 = 4x^2 - x^2

=>P = 1.73x cm.

Now, we know=>

Cot A = 1/TanA = base/perpendicular

=>Cot A = x/1.73 x

=>CotA = 1/1.73.

Remember

1)SinA = 1/CosecA

2)CosA = 1/SecA

3)TanA = 1/CotA

4)SinA = Perpendicular/Hypotenuse

5) Cos A = Base/Hypotenuse

6)TanA = Perpendicular/Base