Question

if sec theata is 25/24 then cosec theta is what​

Answer 1

Step-by-step explanation:

sec Ø=hypotenuse/base=25/24

cosecØ=hypotenuse/perpendicular=25/P

now,to find p we will apply Pythagoras theorem:-

P^2+B^2=H^2

${p}^{2} = {25 }^{2} - {24}^{2}$

${p}^{2} = 625 - 576 = 49$

$p = \sqrt{49 = 7}$

therefore cosecØ=25/7

Answer 2

Step-by-step explanation:

sec theta = H/B

Given : sec theta = 25/24

therefore, H = 25 and B = 24

finding P,

H^2 = P^2 + B^2

=> P^2 = H^2 - B^2

=> P^2 = (25)^2 - (24)^2

=> P^2 = 625 - 576

=> P^2 = 49

=> P = √49

=> P = 7

therefore cosec = H/P = 25/7