If sec theata+ tan theata=p,then what is the value of sec theata - tan theata
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1
Answer:
1/p
Step-by-step explanation:
Hi ,
Here I am using A instead of theta .
It is given that ,
Sec A + tan A = p ---( 1 )
*************"***************************
By Trigonometric identity :
Sec²A - tan² A = 1
Algebraic identity :
a² - b² = ( a + b )( a - b )
********************************************
Sec² A - tan² A = 1
( SecA + tan A )( secA - tanA ) = 1
p × ( sec A - tan A ) = 1 [ from ( 1 ) ]
Sec A - tan A = 1/p
I hope this helps you.
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