Question

if sec theeta + tan theeta -p then sec - theeta tan theeta=?​

Answer 1

Answer:

Given secθ+tanθ=x⋯(1)

As we know that

sec

2

θ−tan

2

θ=1

⟹(secθ−tanθ)(secθ+tanθ)=1 (∵a

2

−b

2

=(a+b)(a−b))

⟹secθ−tanθ=

x

1

⋯(2)

(1)−(2)⟹2tanθ=x−

x

1

=

x

x

2

−1

⟹tanθ=

2x

x

2

−1