If sec theeta + tan theeta = x then sec theeta =
a) (x²+1)/x
b) (x²+1)/2x
c)(x²-1)/2x
d) (x²-1)/x
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Sorry Jungkookie's sweetheart
I'm very bad at maths,so I can't answer your question
Have an Endless Euphorical Happiness with your beloved Kookie by your side
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