Question

If sec theeta =x+1/4x, prove that
Sec theeta + tan theeta=2x or 1/2x

Answer 1

here

secA=(4x2+1)/4x

we know that secA=H/B

then H=4X2+1 AND B=4X

THEN  P2=(4x2+1)2 -(4x)2

=16x4+1+8x2-16x2

=16x4+1-8x2

=(4x2-1)2

P=4x2-1

secA+tanA=H/B+P/B

so, ( 4x2+1)4x+(4x2-1)/4x

8x2/4x=2x

Answer 2

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