Question

if sec theta= 10/6 ,find value of other trigonometric ratios​

Answer 1

Answer:

Let △ABC be right angled triangle (right angled at B)

secQ= AB/AC

=

$6\ \10$

Let AC=10x and AB=6x

AC2=AB 2+BC2

BC2 =AC 2−AB 2x2

=169−144x 2

=25

x= 25

=5

sinQ= AC/BC

= 13x

5x

=

13

5

cosQ=

AC

AB

=

13

12

tanQ=

AB

BC

=

12x

5x

=

12

5

cotQ=

tanQ

1

=

12

5

1

=

5

12

cosec Q=

BC

AC

=

5x

13x

=

5

13