Question

If sec theta=13/5, find the value of (2sin theta-3cos theta/4sin theta-9cos theta) +3 cos theta

Answer 1

Step-by-step explanation:

sec theta= 13/5=H/B

P×P= H×H - B×B (Pythagoras theorem)

= 13×13 - 5×5

= 169 - 25

= 144

P =√144

= 12

sin theta = P/H = 12/13

cos theta= B/H = 5/13

(2sin theta- 3 cos theta/4sin theta- 9 cos theta) +3cos theta

= (24/13- 15/13 / 48/13 - 45/13) - 15/13

= (9/13 /3/13) -15/13

= 3 - 15/13

= 25/13