Question

if sec theta =13/5 show that 2 cos theta minus 3 cos theta by 4 sin theta minus 9 cos theta =3
​

Answer 1

Answer:

information is wrong

Step-by-step explanation:

sec theta = 13/5 = H/B

H^2 = P^2 + B^2

13^2 = p^2 + 5^2

169 - 25 = P^2

144 = P^2

12 = P

so, sin theta = P/H = 12/13

and cos theta = B/H = 5/13

put the value of sin and cos theta in given equation

2(5/13) - 3(5/13)/ 4(12/13) - 9(5/13) = 3

10/13 - 15/13 / 48/13 - 45/13 = 3

-5/13 / 3/13 = 3

-5/13 x 13/3 = 3

-5/3 = 3