Question

if sec theta = 17/8 then prove that 3-4 sin ² theta / 4 cos² theta -3 = 3-tan²theta/ 1-3 tan² theta

pls answer quickly .. it's urgent​

Answer 1

Step-by-step explanation:

sec©=17/8

(3-4sin²©)/(4cos²©-3)=(3-tan²©)/(1-3tan²©)

if sec©=17/8

so cos©= 8/17

sin©=√1-cos²©

sin©=√1-(8/17)²

sin©=√225/289

sin©=15/17

so

tan ©= 15/8

now put value and

get

RHS=LHS

Answer 2

Answer:

khatidk00 answer is correct