If sec theta =17/8 then prove that(sec theta+tan theta) (sec theta-tan theta) =1
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Let theta be A
(Sec A + tan A )( sec A - tan A )
= sec^2 A - tan ^2 A
= 1
(Sec A + tan A )( sec A - tan A )
= sec^2 A - tan ^2 A
= 1
Answered by
3
dear I hope it is clear to you
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