Math, asked by h3896334, 17 days ago

if sec theta = 17/8 verify that (3-4sin2 theta)/4cos2 theta-3)=(3-tan2 theta)/ (1-3tan2 theta)​

Answers

Answered by manjappahosur59424
1

Answer:

ok I will try to solve this problem

Answered by aakhyapatel18jun2012
1

Answer:

If sec A = 17/8, verify that (3-4 sin2A)/(4cos2 A-3) =(3- tan2 A )/(1-3tan2 A)Read more on Sarthaks.com - https://www.sarthaks.com/33921/if-sec-a-17-8-verify-that-3-4-sin-2a-4cos-2-a-3-3-tan-2-a-1-3tan-2-a

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