If sec theta=2 then find all trigonometric ratio
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Step-by-step explanation:
We know that
secθ=
base
hypotenuse
secθ=
1
2
⇒
B
H
=
1
2
⇒
BC
AC
=
1
2
let BC=1k and AC=2k
where k is any positive integer
In right angled △ABC,we have
(AB)
2
+(1k)
2
=(2k)
2
⇒(AB)
2
+(k)
2
=4k
2
⇒(AB)
2
=4k
2
−k
2
=3k
2
⇒AB=k
3
(By Pythagoras theorem)
Now, we have to find the value of other trigonometric ratios
we know that
sinθ=
hypotenuse
Perpendicular
=
AC
AB
=
2k
k
3
=
2
3
cosθ=
hypotenuse
Base
=
AC
BC
=
2k
1k
=
2
1
tanθ=
Base
Perpendicular
=
BC
AB
=
k
k
3
=
1
3
=
3
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