Question

if sec theta = 25/7 then find other ratios with Pythagoras theorem.​

Answer 1

Step-by-step explanation:

sec=25/7

we know that sec theta = hypotenuse/base

25=hypotenuse and 7= base

now we find perpendicular ___

by pythagoras--H square=P square + b square

(25)^2=(p)^2+7^2

625= p square +49

p^2=625-49=576

p=√576=24

24=perpendicular

#sin theta= p/h=24/25#cosec=h/p=25/24

#cos theta=b/h=7/25,#sec theta=h/b=25/7

#tan theta=p/b=24/7,vot theta=b/p=7/24

hope this will help you