Question

if sec theta =3k and tan theta =3/k then k^-1/k^2

Answer 1

Hey friend
Here is a formula
Sec ^2 @ - tan^2 @ = 1

(3k)^2 - (3/k)^2 = 1
9( k^2 - 1/k^2 ) =1
K^2 - 1/k^2 = 1/9

Hope it will help you !!

Answer 2

Answer:

1/9

Step-by-step explanation:

from the 3 identities

by 2nd identity

sec^2theta -tan^2theta=1

given :

(3k)^2-(3/k)^2=1

9k^2-9/k^2=1

9(k^2-1/k^2)=1

k^2-1/k^2=1/9