if sec theta = 7 evaluate cosec theta tan theta + sin theta cosec theta + sin theta sec theta tan theta
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Answer:
sec th =1/cos th
cos th = 1/7
h sq= p sq +b sq
7^2-1^2= p^2
p= √48= 4√3
sin th =p/h=4√3/7
tan th=p/b= 4√3
cosec th=h/p= 7/4√3
(7/4√3×4√3)+(4√3/7×7/4√3)+(4√3/7×7×4√3)
=7+1+48
=56
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