Math, asked by vedantvispute38, 8 months ago

If sec(theta) + B tan(theta) = P what is the value of cos theta?

(a)
 \frac{ {p}^{2}   +  1}{{p}^{2}    -  1}
(b)
 \frac{ {p}^{2}  - 1 }{ {( {p}^{2}  + 1)}^{2}  }
(c)
 \frac{2p}{{p}^{2}   +  1}
(d)
 \frac{4 {p}^{2} }{ {( {p}^{2}  + 1)}^{2} }

Answers

Answered by TheLogophile
5

Answer:

cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1) Ans.

Answered by rina26112
3

Answer:

cosec0=1/sin0=1/(p2-1)/(p2+1)=(p2+1)/(p2-1

Step-by-step explanation:

hope it will help you

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