Question

if sec theta = cos^2 theta then find the value of sin^4theta +2sin^3theta +sin^2theta

Answer 1

Hey friend, Harish here.

Here is your answer.

⇒ sec θ = cos²θ

⇒ 1/cosθ  = cos²θ

⇒ cos³ θ = 1

⇒ cos θ = 1

So, θ = 0 degrees

Now substituting the value we will get answer as :

sin⁴ 0° + 2 sin³ 0° + sin² 0°

⇒ 0⁴ + 2 (0³) + 0² = 0

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Hope my answer is helpful to you.

Answer 2

✌️The answer goes like this!✌️

sec θ = cos²θ

-> 1/cosθ = cos²θ

-> cos³ θ = 1

-> cos θ = 1

So, θ = 0°

Now, substituting the value of θ = 0°, we get

0 + 2(0) + 0 = 0

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