If sec theta = cosec theta and 0º = theta < 90°, find the value of theta.
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Answered by
0
Answer:
∅= 45°. [ I am using this symbol (∅) for theta]
Step-by-step explanation:
sec ∅ = cosec ∅
1/cos ∅ = 1/sin ∅. [ since sec and cosec are reciprocals of sin and cosine]
sin ∅/cos ∅ = 1
tan ∅ = 1 [sin/cos = tan]
tan 45°=1. [the value of tan 45°=1]
So,∅=45°
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Answered by
0
Answer:
45°
Step-by-step explanation:
For, 0°≤theta≤90°
sec(theta)=cosec(theta)
1/cos(theta)=1/sin(theta)
sin(theta)=cos(theta)
-take a both sides square..
-we get,
sin²(theta)=cos²(theta)
sin²(theta)=1-sin²(theta)
2sin²(theta)=1
sin²(thera)=1/2
sin(theta)=1/√2
(theta)=sin^-1 (1/√2)
(theta)=sin^-1 (sin45°)
(theta)=45°
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