Question

If sec theta is equal to 4x and tan theta is 4/x
Find the value of 8(x²-1/x²)

Answer 1

$1 + \tan {}^{2} = \sec {}^{2}$

1 + (4/x)² = 4x²

1 + 16/x² = 16x²

x² + 16 ÷ x² = 16x²

x² + 16 = 16 x^2 x x²

x² + 16 = 16 x⁴

16/16 = x⁴-x²

1=x⁴÷x²

1=x²

√1 = x

x = 1

put x= 1 in the condn

8{(1)²-1÷(1)²}

=8 { 1 - 1/1 }

= 8 {1-1/1}

= 8 {0/1}

= 8 x 0

= 0

hence the answer is 0.

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