Question

if sec theta minus cos theta is equal 5 then find the value of sec square theta plus cos square theta

Answer 1

Answer:23

Step-by-step explanation:

SecQ - cos Q = 5

Squaring both sides

(SecQ - cosQ) ^2 = 5^2

Sec^2Q + cos^2Q - 2 • secQ • cosQ = 25

Sec^2Q + cos^2Q -2 • 1/cosQ • cosQ = 25 { { secQ = 1/cosQ} }

Sec^2Q + cos^2Q -2 = 25

Sec^2Q + cos^2Q = 23

Answer 2

Answer:

The value would be 27

Step-by-step explanation:

Given,

$\sec \theta - \cos \theta = 5$

Squaring both sides,

$(\sec \theta - \cos \theta)^2 = 25$

$(\sec \theta)^2+(\cos \theta)^2-2\sec \theta \cos \theta= 25$

( Using (a - b)² = a² - 2ab + b² )

$\sec^2 \theta + \cos^2 \theta - 2\frac{1}{\cos \theta}\times \cos \theta = 25$

$\sec^2 \theta + \cos^2 \theta - 2= 25$

$\sec^2 \theta + \cos^2 \theta =25+ 2 = 27$

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Trigonometric Formulae :

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