if sec theta plus tan theta is =4. find sin theta and cos theta
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sin theta = 15/17, cos theta= 8/17
Step-by-step explanation:
sec theta+tan theta =4
[1/(cos theta)]+[sin theta/cos theta] =4
(1+sin theta)/cos theta =4
1+sin theta =4 cos theta
Squaring on both sides,
1+sin^2 theta+ 2 sin theta= 16 cos^2 theta
= 16-16 sin^2 theta
17 sin^2 theta+2 sin theta-15= 0
Let sin theta be 'x'
17x^2+2x-15= 0
17x^2+17x-15x-15= 0
17x(x+1) -15(x+1)= 0
(x+1)(17x-15)= 0
x= -1 or x= 15/17; when sin theta= -1, cos theta=0
hence, tan theta is infinity
sin theta= 15/17, cos theta= root(1-sin^2 theta)= 8/17
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