If sec theta+sin theta=2/3 then find sin theta
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sec theta + sin theta = 2/3
cosec(90-theta) + sin theta = 2/3
cosec theta + sin theta = 2/3
1/sin theta + sin theta = 2/3
sin theta + sin² theta/ sin theta = 2/3
sin theta ( 1 + sin theta ) / sin theta = 2/3
1 + sin theta = 2/3
sin theta = 2/3 - 1
sin theta = 2 - 3 /3
sin theta = -1/3
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