If sec theta + tan theta = 1/3, then sec theta
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Given:
sec θ + tan θ = 1/3 -- equation (1).
We know that,
sec² θ - tan² θ = 1
- a² - b² = (a + b)(a - b).
So,
(sec θ + tan θ)(sec θ - tan θ) = 1
Substitute the value of sec θ + tan θ from equation (1).
⟶ 1/3 * (sec θ - tan θ) = 1
⟶ sec θ - tan θ = 3 -- equation (2)
Add equations (1) & (2).
⟶ sec θ + tan θ + sec θ - tan θ = 1/3 + 3
⟶ 2 * sec θ = (1 + 9)/3
⟶ sec θ = (10/3) * (1/2)
⟶ sec θ = 5/3
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