if sec theta +tan theta =2/3 find tan theta and sec theta
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Answer:
secA=13/12 tanA=5/12
Step-by-step explanation:
Since, sec²A-tan²A=1
secA+tanA=2/3
secA-tanA= 3/2
so 2secA=13/6
secA=13/12
tan²A= sec²A-1= (13/12)²-1= (5/12)²
thus tanA=5/12
secA=13/12, tanA=5/12
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