If sec theta+tan theta=5 find the quadrant in which theta lies,find the value of sin theta
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Given
We have sec theta + tan theta = 5
1/cos theta + sin theta /cos theta = 5
1 + sin theta / cos theta = 5
Squaring both sides we get
(1 + sin theta)^2/ cos^2 theta = 25
(1 + sin theta)(1 + sin theta) / (1 – sin^2 theta) = 25
(1 + sin theta)(1 + sin theta) /(1 + sin theta)(1 – sin theta) = 2
1 + sin theta / 1 – sin theta = 25
1 + sin theta = 25(1 – sin theta)
1 + sin theta = 25 – 25 sin theta
26 sin theta = 24
Sin theta = 24/26
Sin theta = 12/13
So sin theta lies in I quadrant
madhavimanchikatla19:
please do it clearly from the step 1+sin theta = 25(1-sin theta
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