Question

if sec theta + tan theta is equal to M and sec theta minus tan theta is N THEN SHOW THAT MN=1

Plz answer but I wont mark it brainiest

Answer 1

Answer:  its a proof

So no numerical answer

Step-by-step explanation:

Answer 2

MN = 1, it is proved.

Step-by-step explanation:

We have,

$\sec \theta+\tan \theta=M$  

and $\sec \theta-\tan \theta=N$]

To prove that, MN = 1.

∴ MN = $(\sec \theta+\tan \theta)(\sec \theta-\tan \theta)$

= $\sec^{2} \theta-\tan^{2} \theta$

[ ∵$(a+b)(a-b)=a^{2} -b^{2}$]

= 1

[∵$\sec^{2} \theta-\tan^{2} \theta=1$]

Hence, MN = 1, it is proved.