if sec theta + tan theta =k. prove that sin theta =k^2-1/k^2+1.
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Step-by-step explanation:
sec theta + tan theta =k ---(i)
sec ^ 2 theta - tan ^ 2 theta = 1
( sec theta - tan theta ) (sec theta +tan theta) =1
sec theta- tan theta= 1/k ---(ii)
from (i) and (ii)
2sec theta = k+1/k = k^2 +1 /k
sec theta = k^2 +1 / 2k
cos theta = 2k /1+ k^2
sin theta = k^2- 1/ k^ 2+1
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