Question

If sec theta + tan theta = k then prove the sec theta = k^2-1/k^2+1

Answer 1

Answer:

question is wrong

secØ ≠ k²-1/k²+1

Step-by-step explanation:

secØ+tanØ = k

use, sec²Ø-tan²Ø = 1

(secØ+tanØ)(secØ-tanØ) = 1

k.(secØ-tanØ) = 1 , then

secØ-tanØ = 1/k

Now,

secØ+tanØ + secØ-tanØ = k+1/k

2secØ = (k²+1)/k

secØ = (k²+1)/2k ≠ k²-1/k²+1