if sec theta+ tan theta=m then tan theta is equal to
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Solution:
Given,
sec θ + tan θ = p….(i)
We know that,
sec2θ – tan2θ = 1
(sec θ + tan θ)(sec θ – tan θ) = 1
p(sec θ – tan θ) = 1
sec θ – tan θ = 1/p….(ii)
Subtracting (ii) from (i),
sec θ + tan θ – sec θ + tan θ = p – (1/p)
2 tan θ = (p2 – 1)/p
tan θ = (p2 – 1)/2p
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