If sec theta + tan theta = p, show that sec theta - tan theta =1/p
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Heya,
According to trigonometry identity sec²θ - tan²θ = 1
So, we can write this trigonometry identity as;
(secθ - tanθ)(secθ + tanθ) = 1 ..... equation 1
It is given in question that secθ + tanθ = p
But putting this value in equation 1, we will get;
(secθ - tanθ)(p) = 1
secθ - tanθ = 1/p
Hence proved.
Hope this helps you...:)
According to trigonometry identity sec²θ - tan²θ = 1
So, we can write this trigonometry identity as;
(secθ - tanθ)(secθ + tanθ) = 1 ..... equation 1
It is given in question that secθ + tanθ = p
But putting this value in equation 1, we will get;
(secθ - tanθ)(p) = 1
secθ - tanθ = 1/p
Hence proved.
Hope this helps you...:)
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