Question

If sec theta+ tan theta =P, then find the value of cose.​

Answer 1

Answer:

sec+tan=P

1/cos+sin/cos=P

(sin+1)/cos=P

(sin+1)^2/(1-sin)^2=P^2

(sin+1)/(1-sin)=P^2

sin+1=P^2-P^2sin

sin+P^2sin=P^2-1

sin=(P^2-1)/(1+P^2)

cosec=(1+P^2)/(1-P^2)