Question

if sec theta+ tan theta= p then find the value of sin theta in terms of'p'​

Answer 1

Step-by-step explanation:

i hope this is correct

sintheatais equals to 1-p'2/1+p'2

Answer 2

Answer:

$sinx =\frac{p^2-1}{p^2+1}$

Step-by-step explanation:

$-> secx+tanx=p$

$-> secx+tanx=\frac{1}{p}$ $[( secx-tanx)(secx+tanx)=sec^2x-tan^2x=(p)(\frac{1}{p})=1]$

By adding and subtracting the equation you get,

$=>secx=\frac{p^2+1}{2p}$  $\&$ $tanx=\frac{p^2-1}{2p}$

$=> cosx=\frac{2p}{p^2+1}$

We all know,

$=> (cosx)(tanx)=sinx$

$=> sinx=(\frac{2p}{p^2+1})(\frac{p^2-1}{2p})=\frac{p^2-1}{p^2+1}$

Brainliest?