if sec theta+tan theta=p then find the value ofsec theta-tan theta?
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Step-by-step explanation:
Hi,
Here I am using A instead of theta.
It is given that,
Sec A + tan A = p ---(1)
By Trigonometric identity :
Sec?A - tan? A = 1
Algebraic identity :
a? - b? = ( a + b )(a - b)
Sec? A - tan? A = 1
( SecA + tan A )( secA - tanA ) = 1
p x ( sec A - tan A ) = 1[ from (1)]
Sec A - tan A = 1/p
I hope this helps you.
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