Question

if sec theta + tan theta = p then sec theta - tan theta​

Answer 1

Answer:

sec∅-tan∅ = 1/p

Step-by-step explanation:

sec∅ + tan∅ = p

=> 1/sec∅+tan∅ = 1/p

=> (sec∅ - tan∅) / (sec∅-tan∅)(sec∅+tan∅) = 1/p

=> (sec∅ - tan∅) / (sec^2∅-tan^2∅) = 1/p

=> (sec∅ - tan∅) = 1/p

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Answer 2

Answer:

Answer:

Bhangar: Continuous deposition of alluvium.

Bhangar: That part where flood water cannot

reach.

Khadar:flood water spreads every year and thin layer of soil spreads.

Khadar:Renewal of soil every year.