If sec theta × tan theta = r, then the value of sec^6 theta-tan^6 theta is
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Answer:
LHS =sec
6
θ
=(1+tan
2
θ)
3
=1+tan
6
θ+3tan
4
θ+3tan
2
θ
=1+tan
6
θ+3tan
2
θ(1+tan
2
θ)
=1+tan
6
θ+3tan
2
θsec
2
θ
=RHS
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