If sec theta + tan theta =x, then sec theta =?
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Step-by-step explanation:
seca+tana=x
Squaring
sec^2a-tan^2=1
(seca+tana)(seca-tana)=1
seca-tana=1/x....(1)
seca+tana=x...(2)
-----------------------------------
2seca=x+1/x
similarly
2tana=(x-1/x)
secatana=(x+1/x)(x-1/x)/4=(x^2-1/x^2)/4=(1/4)(x^2-1/x2)
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