Question

If sec theta +tan theta = x,then tan theta =?

Answer 1

Step-by-step explanation:

$\sec( \alpha ) + \tan( \alpha ) = x \\ { \sec( \alpha ) }^{2} = {(x - \tan( \alpha )) }^{2} \\ 1 + { \tan( \alpha ) }^{2} = {x}^{2} + { \tan( \alpha ) }^{2} - 2x \tan( \alpha) \\ 2x \tan( \alpha ) = {x}^{2} - 1 \\ \tan( \alpha ) = \frac{ {x}^{2} - 1 }{2x}$